169x^2+10x-225=0

Solution for 169x^2+10x-225=0 equation:

169x^2+10x-225=0

a = 169; b = 10; c = -225;
Δ = b2-4ac
Δ = 102-4·169·(-225)
Δ = 152200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{152200}=\sqrt{100*1522}=\sqrt{100}*\sqrt{1522}=10\sqrt{1522}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{1522}}{2*169}=\frac{-10-10\sqrt{1522}}{338}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{1522}}{2*169}=\frac{-10+10\sqrt{1522}}{338}
$